y=mx+b [Social][Recruiting]

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Re: y=mx+b [Social][Recruiting]

Postby TA1LGUNN3R on Mon Mar 28, 2011 12:09 pm

Crazyirishman wrote:
Crazyirishman wrote:AoG is there a lazy-persons way to do partial fraction decompositions and integration involving centroids?


And trigonometric substitutions into integrals. I'm not allowed to use my calculator in this class so I actually have to start paying attention in Calc 2.


Trig subs are really easy, you just have to remember which one to use. In my class last semester all our tests were open book, so I dog-eared the page with the chart. It pretty much just comes down to simplifying the x^2+/-a^2 or a^2-x^2 under the square root to a^2(trig function)^2, which cancels out to just a*trig function, multiplied by the d/dx of your substitution of course. But there isn't a simpler way that I know of, that way is pretty short anyway.

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Re: y=mx+b [Social][Recruiting]

Postby Army of GOD on Mon Mar 28, 2011 12:39 pm

Centroids? I've never even heard of that word!

And there isn't a lazy way to to PFDs except just to skip a few steps. Like, once I am able to get the denominator of the rational number into its irreducible form, I just go automatically into (denominator)=A(shit)+B(f*ck). PFDs are ridiculously simple to check though (just add the fractions...).

Trig sub was actually the hardest part of Calc II for me because I skipped all of those classes...haha. The main thing is to make sure, like TG said, to substitute your d/dx and shit for theta and whatnot. It's kind of a bitch.
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Re: y=mx+b [Social][Recruiting]

Postby Crazyirishman on Mon Mar 28, 2011 2:45 pm

My calc class is engineering based and so the 'centroids' I guess could also be called the center of mass or center of momentum.
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Re: y=mx+b [Social][Recruiting]

Postby maasman on Mon Mar 28, 2011 2:49 pm

Crazyirishman wrote:My calc class is engineering based and so the 'centroids' I guess could also be called the center of mass or center of momentum.

aren't those the curves you get if you rolled a circle on a line?
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Re: y=mx+b [Social][Recruiting]

Postby Army of GOD on Mon Mar 28, 2011 3:07 pm

maasman wrote:
Crazyirishman wrote:My calc class is engineering based and so the 'centroids' I guess could also be called the center of mass or center of momentum.

aren't those the curves you get if you rolled a circle on a line and then smoked it?


Fixed.
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Re: y=mx+b [Social][Recruiting]

Postby DoomYoshi on Thu Apr 28, 2011 2:33 pm

maasman wrote:
Crazyirishman wrote:My calc class is engineering based and so the 'centroids' I guess could also be called the center of mass or center of momentum.

aren't those the curves you get if you rolled a circle on a line?


That is a cycloid you are thinking of.

Anyways, Victor if I could join that would be awesome. My specialties are Set Theory and Statistical Theory, so if you are looking for applied math help, you need to ask someone else.
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Re: y=mx+b [Social][Recruiting]

Postby Mr_Adams on Thu Jun 02, 2011 2:42 pm

Sign me up. If you guys are really nice, I might even help with your calc homework.
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Re: y=mx+b [Social][Recruiting]

Postby usernamer on Sat Jun 04, 2011 7:25 am

can i join plz? love maths, plan to do it at uni in a couple of years and got a couple of questions for you lot :)
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Re: y=mx+b [Social][Recruiting]

Postby Mr_Adams on Sat Jun 04, 2011 10:51 am

for example, "Riemann hypothesis, WTF?!?"
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Re: y=mx+b [Social][Recruiting]

Postby maxfaraday on Tue Mar 06, 2012 8:07 pm

In please!
I think I can help here.
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Re: y=mx+b [Social][Recruiting]

Postby nietzsche on Mon Apr 09, 2012 3:53 am

I was once an Ace on math, better than everybody here including AoG and VS.

I got a medal on 1st place in math in the whole state.

So if you need help ask me.

Wait, I had too many beers in my early 20s, i forgot it all.
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Re: y=mx+b [Social][Recruiting]

Postby maxfaraday on Mon Apr 09, 2012 4:39 am

nietzsche wrote:I was once an Ace on math, better than everybody here including AoG and VS.

I got a medal on 1st place in math in the whole state.

So if you need help ask me.

Wait, I had too many beers in my early 20s, i forgot it all.


Sounds familiar... but I don't remember exactely.
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Re: y=mx+b [Social][Recruiting]

Postby DoomYoshi on Fri Jul 05, 2013 4:46 pm

Ok, we lost our leader but we are looking for a new one.
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Re: y=mx+b [Social][Recruiting]

Postby nietzsche on Sat Jul 06, 2013 2:40 am

maxfaraday wrote:
nietzsche wrote:I was once an Ace on math, better than everybody here including AoG and VS.

I got a medal on 1st place in math in the whole state.

So if you need help ask me.

Wait, I had too many beers in my early 20s, i forgot it all.


Sounds familiar... but I don't remember exactely.


Lol, I meant meth. Damn typos.
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Re: y=mx+b [Social][Recruiting]

Postby gcwca_4_life on Sat Jul 13, 2013 5:12 pm

So, whom is in charge?


Who ever it is right now, itd be awesome for you to message meh! :)


Thanks. Gcw. :)
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Re: y=mx+b [Social][Recruiting]

Postby Metsfanmax on Sat Jul 13, 2013 11:29 pm

gcwca_4_life wrote:So, whom is in charge?


Who ever it is right now, itd be awesome for you to message meh! :)


Thanks. Gcw. :)


I'm the usergroup leader for this for the indefinite future.
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Re: y=mx+b [Social][Recruiting]

Postby notyou2 on Sat Apr 19, 2014 9:38 pm

Where did you hide Victor's body?
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Re: y=mx+b [Social][Recruiting]

Postby sempaispellcheck on Mon Apr 21, 2014 11:26 am

notyou2 wrote:Where did you hide Victor's body?

He is buried with the proof of Fermat's Last Theorem.
That is all that will be said on this matter.

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