y=mx+b [Social][Recruiting]

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Re: y=mx+b [Social][Recruiting]

Postby Victor Sullivan on Thu Mar 03, 2011 11:28 pm

thebest712 wrote:have tomorrow math olympiad :P

Oo, how did it go??

(By the way, the usergroup should be up soon. king achilles just had some minor things, including removing AoG as group leader to focus on his clan and a description of the group.)
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Re: y=mx+b [Social][Recruiting]

Postby tkr4lf on Thu Mar 03, 2011 11:35 pm

Sweet! Don't forget to add me...I need this! I just got a 70 something on my test in elementary algebra...granted most of the points off were me forgetting to put the negative sign back on the final answer after dividing a large negative by a positive...stupid mistakes like that...but I still need the help!
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Re: y=mx+b [Social][Recruiting]

Postby Army of GOD on Thu Mar 03, 2011 11:38 pm

Victor Sullivan wrote:
thebest712 wrote:have tomorrow math olympiad :P

Oo, how did it go??

(By the way, the usergroup should be up soon. king achilles just had some minor things, including removing AoG as group leader to focus on his clan and a description of the group.)



lol. They just don't trust me as group leader. All because of QQ
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Re: y=mx+b [Social][Recruiting]

Postby Victor Sullivan on Thu Mar 03, 2011 11:53 pm

The forum's up :)
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Re: y=mx+b [Social][Recruiting]

Postby Victor Sullivan on Thu Mar 03, 2011 11:58 pm

And everyone has been officially added.
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Re: y=mx+b [Social][Recruiting]

Postby thebest712 on Fri Mar 04, 2011 2:17 am

Army of GOD wrote:
Victor Sullivan wrote:
thebest712 wrote:have tomorrow math olympiad :P

Oo, how did it go??

(By the way, the usergroup should be up soon. king achilles just had some minor things, including removing AoG as group leader to focus on his clan and a description of the group.)



lol. They just don't trust me as group leader. All because of QQ

uhm didnt had enough time and make some stupid mistakes:: 21/6= 3 :?
have 20/30... think I would need 22 to go to final
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Re: y=mx+b [Social][Recruiting]

Postby Crazyirishman on Tue Mar 08, 2011 7:24 pm

Can you teach me to count?
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Re: y=mx+b [Social][Recruiting]

Postby TA1LGUNN3R on Tue Mar 22, 2011 12:11 am

i r can join?

I've got Calc III next semester, and I was starting to struggle with the last few chapters of II. Also, will you be able to provide help in physics? I've got to finish my physics sequence, I stopped at 211. I need to take 212/213, which won't start until next winter. That would also help.

-TG
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Re: y=mx+b [Social][Recruiting]

Postby Army of GOD on Tue Mar 22, 2011 12:16 am

TG, the numbers of your classes don't really help; we all don't go to your school. I can help though in both Calc and Physics (am taking Calc III currently, have only been to 4 classes and would have an A if I remembered to do my hw).
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Re: y=mx+b [Social][Recruiting]

Postby TA1LGUNN3R on Tue Mar 22, 2011 12:28 am

Oh well in Oregon most of the math and science classes are the same number, because there is a lot of transfer from community colleges. 212/213 I assume would be Phy II and III with a Calc base. The books we use are retarded, I can't understand anything they say.

-TG
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Re: y=mx+b [Social][Recruiting]

Postby Army of GOD on Tue Mar 22, 2011 1:10 am

Haha Physics III? Is that Modern Physics for you? We had Physics I, II and then first semester of sophomore year I took Modern. Relativity is a bitch just because it doesn't make sense. But I should be able to help you. Most of Physics II is cake though.
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Re: y=mx+b [Social][Recruiting]

Postby karelpietertje on Tue Mar 22, 2011 6:12 am

Physics student wanting in!
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Re: y=mx+b [Social][Recruiting]

Postby Crazyirishman on Sun Mar 27, 2011 6:09 pm

AoG is there a lazy-persons way to do partial fraction decompositions and integration involving centroids?
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Re: y=mx+b [Social][Recruiting]

Postby greenoaks on Mon Mar 28, 2011 10:46 am

i just finished watching the 4 part BBC series A History Of Mathematics. i loved it.

have you seen it Victor ?
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Re: y=mx+b [Social][Recruiting]

Postby Crazyirishman on Mon Mar 28, 2011 10:58 am

Crazyirishman wrote:AoG is there a lazy-persons way to do partial fraction decompositions and integration involving centroids?


And trigonometric substitutions into integrals. I'm not allowed to use my calculator in this class so I actually have to start paying attention in Calc 2.
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Re: y=mx+b [Social][Recruiting]

Postby TA1LGUNN3R on Mon Mar 28, 2011 12:09 pm

Crazyirishman wrote:
Crazyirishman wrote:AoG is there a lazy-persons way to do partial fraction decompositions and integration involving centroids?


And trigonometric substitutions into integrals. I'm not allowed to use my calculator in this class so I actually have to start paying attention in Calc 2.


Trig subs are really easy, you just have to remember which one to use. In my class last semester all our tests were open book, so I dog-eared the page with the chart. It pretty much just comes down to simplifying the x^2+/-a^2 or a^2-x^2 under the square root to a^2(trig function)^2, which cancels out to just a*trig function, multiplied by the d/dx of your substitution of course. But there isn't a simpler way that I know of, that way is pretty short anyway.

-TG
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Re: y=mx+b [Social][Recruiting]

Postby Army of GOD on Mon Mar 28, 2011 12:39 pm

Centroids? I've never even heard of that word!

And there isn't a lazy way to to PFDs except just to skip a few steps. Like, once I am able to get the denominator of the rational number into its irreducible form, I just go automatically into (denominator)=A(shit)+B(f*ck). PFDs are ridiculously simple to check though (just add the fractions...).

Trig sub was actually the hardest part of Calc II for me because I skipped all of those classes...haha. The main thing is to make sure, like TG said, to substitute your d/dx and shit for theta and whatnot. It's kind of a bitch.
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Re: y=mx+b [Social][Recruiting]

Postby Crazyirishman on Mon Mar 28, 2011 2:45 pm

My calc class is engineering based and so the 'centroids' I guess could also be called the center of mass or center of momentum.
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Re: y=mx+b [Social][Recruiting]

Postby maasman on Mon Mar 28, 2011 2:49 pm

Crazyirishman wrote:My calc class is engineering based and so the 'centroids' I guess could also be called the center of mass or center of momentum.

aren't those the curves you get if you rolled a circle on a line?
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Re: y=mx+b [Social][Recruiting]

Postby Army of GOD on Mon Mar 28, 2011 3:07 pm

maasman wrote:
Crazyirishman wrote:My calc class is engineering based and so the 'centroids' I guess could also be called the center of mass or center of momentum.

aren't those the curves you get if you rolled a circle on a line and then smoked it?


Fixed.
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Re: y=mx+b [Social][Recruiting]

Postby DoomYoshi on Thu Apr 28, 2011 2:33 pm

maasman wrote:
Crazyirishman wrote:My calc class is engineering based and so the 'centroids' I guess could also be called the center of mass or center of momentum.

aren't those the curves you get if you rolled a circle on a line?


That is a cycloid you are thinking of.

Anyways, Victor if I could join that would be awesome. My specialties are Set Theory and Statistical Theory, so if you are looking for applied math help, you need to ask someone else.
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Re: y=mx+b [Social][Recruiting]

Postby Mr_Adams on Thu Jun 02, 2011 2:42 pm

Sign me up. If you guys are really nice, I might even help with your calc homework.
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Re: y=mx+b [Social][Recruiting]

Postby usernamer on Sat Jun 04, 2011 7:25 am

can i join plz? love maths, plan to do it at uni in a couple of years and got a couple of questions for you lot :)
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Re: y=mx+b [Social][Recruiting]

Postby Mr_Adams on Sat Jun 04, 2011 10:51 am

for example, "Riemann hypothesis, WTF?!?"
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Re: y=mx+b [Social][Recruiting]

Postby maxfaraday on Tue Mar 06, 2012 8:07 pm

In please!
I think I can help here.
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