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Re: y=mx+b [Social][Recruiting]

PostPosted: Thu Mar 03, 2011 11:28 pm
by Victor Sullivan
thebest712 wrote:have tomorrow math olympiad :P

Oo, how did it go??

(By the way, the usergroup should be up soon. king achilles just had some minor things, including removing AoG as group leader to focus on his clan and a description of the group.)

Re: y=mx+b [Social][Recruiting]

PostPosted: Thu Mar 03, 2011 11:35 pm
by tkr4lf
Sweet! Don't forget to add me...I need this! I just got a 70 something on my test in elementary algebra...granted most of the points off were me forgetting to put the negative sign back on the final answer after dividing a large negative by a positive...stupid mistakes like that...but I still need the help!

Re: y=mx+b [Social][Recruiting]

PostPosted: Thu Mar 03, 2011 11:38 pm
by Army of GOD
Victor Sullivan wrote:
thebest712 wrote:have tomorrow math olympiad :P

Oo, how did it go??

(By the way, the usergroup should be up soon. king achilles just had some minor things, including removing AoG as group leader to focus on his clan and a description of the group.)



lol. They just don't trust me as group leader. All because of QQ

Re: y=mx+b [Social][Recruiting]

PostPosted: Thu Mar 03, 2011 11:53 pm
by Victor Sullivan
The forum's up :)

Re: y=mx+b [Social][Recruiting]

PostPosted: Thu Mar 03, 2011 11:58 pm
by Victor Sullivan
And everyone has been officially added.

Re: y=mx+b [Social][Recruiting]

PostPosted: Fri Mar 04, 2011 2:17 am
by thebest712
Army of GOD wrote:
Victor Sullivan wrote:
thebest712 wrote:have tomorrow math olympiad :P

Oo, how did it go??

(By the way, the usergroup should be up soon. king achilles just had some minor things, including removing AoG as group leader to focus on his clan and a description of the group.)



lol. They just don't trust me as group leader. All because of QQ

uhm didnt had enough time and make some stupid mistakes:: 21/6= 3 :?
have 20/30... think I would need 22 to go to final

Re: y=mx+b [Social][Recruiting]

PostPosted: Tue Mar 08, 2011 7:24 pm
by Crazyirishman
Can you teach me to count?

Re: y=mx+b [Social][Recruiting]

PostPosted: Tue Mar 22, 2011 12:11 am
by TA1LGUNN3R
i r can join?

I've got Calc III next semester, and I was starting to struggle with the last few chapters of II. Also, will you be able to provide help in physics? I've got to finish my physics sequence, I stopped at 211. I need to take 212/213, which won't start until next winter. That would also help.

-TG

Re: y=mx+b [Social][Recruiting]

PostPosted: Tue Mar 22, 2011 12:16 am
by Army of GOD
TG, the numbers of your classes don't really help; we all don't go to your school. I can help though in both Calc and Physics (am taking Calc III currently, have only been to 4 classes and would have an A if I remembered to do my hw).

Re: y=mx+b [Social][Recruiting]

PostPosted: Tue Mar 22, 2011 12:28 am
by TA1LGUNN3R
Oh well in Oregon most of the math and science classes are the same number, because there is a lot of transfer from community colleges. 212/213 I assume would be Phy II and III with a Calc base. The books we use are retarded, I can't understand anything they say.

-TG

Re: y=mx+b [Social][Recruiting]

PostPosted: Tue Mar 22, 2011 1:10 am
by Army of GOD
Haha Physics III? Is that Modern Physics for you? We had Physics I, II and then first semester of sophomore year I took Modern. Relativity is a bitch just because it doesn't make sense. But I should be able to help you. Most of Physics II is cake though.

Re: y=mx+b [Social][Recruiting]

PostPosted: Tue Mar 22, 2011 6:12 am
by karelpietertje
Physics student wanting in!

Re: y=mx+b [Social][Recruiting]

PostPosted: Sun Mar 27, 2011 6:09 pm
by Crazyirishman
AoG is there a lazy-persons way to do partial fraction decompositions and integration involving centroids?

Re: y=mx+b [Social][Recruiting]

PostPosted: Mon Mar 28, 2011 10:46 am
by greenoaks
i just finished watching the 4 part BBC series A History Of Mathematics. i loved it.

have you seen it Victor ?

Re: y=mx+b [Social][Recruiting]

PostPosted: Mon Mar 28, 2011 10:58 am
by Crazyirishman
Crazyirishman wrote:AoG is there a lazy-persons way to do partial fraction decompositions and integration involving centroids?


And trigonometric substitutions into integrals. I'm not allowed to use my calculator in this class so I actually have to start paying attention in Calc 2.

Re: y=mx+b [Social][Recruiting]

PostPosted: Mon Mar 28, 2011 12:09 pm
by TA1LGUNN3R
Crazyirishman wrote:
Crazyirishman wrote:AoG is there a lazy-persons way to do partial fraction decompositions and integration involving centroids?


And trigonometric substitutions into integrals. I'm not allowed to use my calculator in this class so I actually have to start paying attention in Calc 2.


Trig subs are really easy, you just have to remember which one to use. In my class last semester all our tests were open book, so I dog-eared the page with the chart. It pretty much just comes down to simplifying the x^2+/-a^2 or a^2-x^2 under the square root to a^2(trig function)^2, which cancels out to just a*trig function, multiplied by the d/dx of your substitution of course. But there isn't a simpler way that I know of, that way is pretty short anyway.

-TG

Re: y=mx+b [Social][Recruiting]

PostPosted: Mon Mar 28, 2011 12:39 pm
by Army of GOD
Centroids? I've never even heard of that word!

And there isn't a lazy way to to PFDs except just to skip a few steps. Like, once I am able to get the denominator of the rational number into its irreducible form, I just go automatically into (denominator)=A(shit)+B(f*ck). PFDs are ridiculously simple to check though (just add the fractions...).

Trig sub was actually the hardest part of Calc II for me because I skipped all of those classes...haha. The main thing is to make sure, like TG said, to substitute your d/dx and shit for theta and whatnot. It's kind of a bitch.

Re: y=mx+b [Social][Recruiting]

PostPosted: Mon Mar 28, 2011 2:45 pm
by Crazyirishman
My calc class is engineering based and so the 'centroids' I guess could also be called the center of mass or center of momentum.

Re: y=mx+b [Social][Recruiting]

PostPosted: Mon Mar 28, 2011 2:49 pm
by maasman
Crazyirishman wrote:My calc class is engineering based and so the 'centroids' I guess could also be called the center of mass or center of momentum.

aren't those the curves you get if you rolled a circle on a line?

Re: y=mx+b [Social][Recruiting]

PostPosted: Mon Mar 28, 2011 3:07 pm
by Army of GOD
maasman wrote:
Crazyirishman wrote:My calc class is engineering based and so the 'centroids' I guess could also be called the center of mass or center of momentum.

aren't those the curves you get if you rolled a circle on a line and then smoked it?


Fixed.

Re: y=mx+b [Social][Recruiting]

PostPosted: Thu Apr 28, 2011 2:33 pm
by DoomYoshi
maasman wrote:
Crazyirishman wrote:My calc class is engineering based and so the 'centroids' I guess could also be called the center of mass or center of momentum.

aren't those the curves you get if you rolled a circle on a line?


That is a cycloid you are thinking of.

Anyways, Victor if I could join that would be awesome. My specialties are Set Theory and Statistical Theory, so if you are looking for applied math help, you need to ask someone else.

Re: y=mx+b [Social][Recruiting]

PostPosted: Thu Jun 02, 2011 2:42 pm
by Mr_Adams
Sign me up. If you guys are really nice, I might even help with your calc homework.

Re: y=mx+b [Social][Recruiting]

PostPosted: Sat Jun 04, 2011 7:25 am
by usernamer
can i join plz? love maths, plan to do it at uni in a couple of years and got a couple of questions for you lot :)

Re: y=mx+b [Social][Recruiting]

PostPosted: Sat Jun 04, 2011 10:51 am
by Mr_Adams
for example, "Riemann hypothesis, WTF?!?"

Re: y=mx+b [Social][Recruiting]

PostPosted: Tue Mar 06, 2012 8:07 pm
by maxfaraday
In please!
I think I can help here.