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If you know that the other person has neither joker, the odds he has a set with 3 cards are 33.41%; the odds he has a set if he has 4 cards are 77.80%.
macbone wrote:Yep, 7/9 is correct.
Here's some analysis:If you know that the other person has neither joker, the odds he has a set with 3 cards are 33.41%; the odds he has a set if he has 4 cards are 77.80%.
kylegraves1 wrote:7/9 is correct
idk why i have trouble getting them though
macbone wrote:
He's evaluating the board game Risk, a world domination game that uses cards instead of spoils, but the principles are the same. =)
anonymus wrote:macbone wrote:
He's evaluating the board game Risk, a world domination game that uses cards instead of spoils, but the principles are the same. =)
i have to check out this "risk" you talk about..
/
TDK wrote:Interesting, it certainly doesn't SEEM like 7/9...
And since when do you get to play Risk (the board game) with people from all over the world? It's much more fun this way. Although now that I think about it, I'm much better at beating friends and family members than all-comers.
betiko wrote:macbone wrote:Yep, 7/9 is correct.
Here's some analysis:If you know that the other person has neither joker, the odds he has a set with 3 cards are 33.41%; the odds he has a set if he has 4 cards are 77.80%.
33,41?? why is that? i would v'e said 33.34%.
also about the 4 cards odds, i disregard the 3 first ones, and i just think of the odds of getting a set before receiving my 4th, which would be 66.66%. But if you look at it as a whole, you are right, 77.78%
betiko wrote:macbone wrote:Yep, 7/9 is correct.
Here's some analysis:If you know that the other person has neither joker, the odds he has a set with 3 cards are 33.41%; the odds he has a set if he has 4 cards are 77.80%.
33,41?? why is that? i would v'e said 33.34%.
also about the 4 cards odds, i disregard the 3 first ones, and i just think of the odds of getting a set before receiving my 4th, which would be 66.66%. But if you look at it as a whole, you are right, 77.78%
Viceroy63 wrote:Ok; I follow this thread so far but can any one calculate the odds of getting a rainbow (one card of each color) in 4 cards? Now that I would like to see done.
Boys, break out your calculators?
Oh; And how come we don't have joker spoils? Does anyone know?
I think that is a good question.
Viceroy63 wrote:Ok; I follow this thread so far but can any one calculate the odds of getting a rainbow (one card of each color) in 4 cards? Now that I would like to see done.
Boys, break out your calculators?
Oh; And how come we don't have joker spoils? Does anyone know?
I think that is a good question.
Viceroy63 wrote:Oddly enough, I think that I understand.
So If I already have two different colors in three cards then the odds are the same (one in three) of getting a rainbow as getting a set of the same colors.
So I would have a one in three chance of getting something either a rainbow or a flush on that fourth card. One in three is still pretty low.
Thank you for that enlightening comment. =)
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