Moderator: Community Team
betiko wrote:macbone wrote:Yep, 7/9 is correct.
Here's some analysis:If you know that the other person has neither joker, the odds he has a set with 3 cards are 33.41%; the odds he has a set if he has 4 cards are 77.80%.
33,41?? why is that? i would v'e said 33.34%.
also about the 4 cards odds, i disregard the 3 first ones, and i just think of the odds of getting a set before receiving my 4th, which would be 66.66%. But if you look at it as a whole, you are right, 77.78%
Viceroy63 wrote:Ok; I follow this thread so far but can any one calculate the odds of getting a rainbow (one card of each color) in 4 cards? Now that I would like to see done.
Boys, break out your calculators?
Oh; And how come we don't have joker spoils? Does anyone know?
I think that is a good question.
Viceroy63 wrote:Ok; I follow this thread so far but can any one calculate the odds of getting a rainbow (one card of each color) in 4 cards? Now that I would like to see done.
Boys, break out your calculators?
Oh; And how come we don't have joker spoils? Does anyone know?
I think that is a good question.
Viceroy63 wrote:Oddly enough, I think that I understand.
So If I already have two different colors in three cards then the odds are the same (one in three) of getting a rainbow as getting a set of the same colors.
So I would have a one in three chance of getting something either a rainbow or a flush on that fourth card. One in three is still pretty low.
Thank you for that enlightening comment. =)
Return to Conquer Club Discussion
Users browsing this forum: ReDBuLLS