by sempaispellcheck on Fri Feb 20, 2015 2:41 pm
Let's say at the time you start adding troops, you have A troops and your opponent has B troops.
After C turns, you will have (C x Y) + A troops, and your opponent will have (C x X) + B troops.
You want C such that:
(C x Y) + A = 3((C x X) + B)
(C x Y) + A = (C x 3X) + 3B
C x Y = (C x 3X) + 3B - A
Y = 3X + (3B/C) - (A/C)
(3B - A)/C = Y - 3X
C = (3B - A)/(Y - 3X)
Now you simply plug in your values for A, B, X, and Y and solve.
sempai
High score: 2200 - July 20, 2015
Game 13890915 - in which I helped clinch the NC4 title for LHDD