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John Kerry wrote:We will engage in this campaign for as long as it takes to prevail.
josko.ri wrote:I suggest to change the 15 games rule from this:
1) Players A,B,C need to have 15 or more wins together
into this:
1) Players A,B,C need to have 15 or more triples wins together
OR
2) If players A,B,C have n triples wins together (n<15), they can still qualify if:
Players A,B have (15-n) or more triples wins together
&
Players A,C have (15-n) or more triples wins together
&
Players B,C have (15-n) or more triples wins together
If all 3 players have 15+ wins in triples game among themselves, but just do not have it achieved playing as one team but rather playing as 2 of them together and a third player, that is the same value like if they played it together.
Notice, if a triples team has never played together, that means they can still qualify with rule (2) but it means the other 45 games (15 games in combination of every player) need to be achieved.
Gilligan wrote:So let me understand that properly -
Gilligan, SuperWang, Peter Gibbons - 12 wins together.
Gilligan and Peter Gibbons have won 8 triples games without SuperWang.
Gilligan and SuperWang have won 15 triples games without Peter Gibbons.
SuperWang and Peter Gibbons have won 5 games without Gilligan.
Does this mean that we qualify? The way I see it, part in 2) means we only need 2 wins without the other player apiece.
angola wrote:Will all 12 first round games start at once? That is a bit much for triples games.
hyposquasher wrote:angola wrote:Will all 12 first round games start at once? That is a bit much for triples games.
Today is the last day to register but we are still awaiting an answer to this question from a week ago.
If the game load is reasonable we would like to sign up with angola, jetsetwilly, hyposquasher.
Would like an answer to this question, though.
stealth99 wrote:We'd like to play in this thing and we're not sure if we qualify so here goes:
stealth99
conquerhero
bpt777
We have 5 wins as a complete team.
stealth99 and conquerhero have 10 trips wins together.
stealth99 and bpt777 have 7 trips wins together.
bpt777 and conquerhero have 5 trips wins together.
stealth99 wrote:We'd like to play in this thing and we're not sure if we qualify so here goes:
stealth99
conquerhero
bpt777
We have 5 wins as a complete team.
stealth99 and conquerhero have 10 trips wins together.
stealth99 and bpt777 have 7 trips wins together.
bpt777 and conquerhero have 5 trips wins together.
hyposquasher wrote:angola wrote:Will all 12 first round games start at once? That is a bit much for triples games.
Today is the last day to register but we are still awaiting an answer to this question from a week ago.
If the game load is reasonable we would like to sign up with angola, jetsetwilly, hyposquasher.
Would like an answer to this question, though.
hyposquasher wrote:hyposquasher wrote:angola wrote:Will all 12 first round games start at once? That is a bit much for triples games.
Today is the last day to register but we are still awaiting an answer to this question from a week ago.
If the game load is reasonable we would like to sign up with angola, jetsetwilly, hyposquasher.
Would like an answer to this question, though.
Thanks for answering this, we qualify and would like to be in, please
josko.ri wrote:Josko.ri, Moonchild, Rodion sign us in please. Moonchild and Rodion needs 1 more win together to be eligible, and they will make it until 10th April when the tournament starts.
josko.ri wrote:Thanks to Dukasaur or accepting the proposalGilligan wrote:So let me understand that properly -
Gilligan, SuperWang, Peter Gibbons - 12 wins together.
Gilligan and Peter Gibbons have won 8 triples games without SuperWang.
Gilligan and SuperWang have won 15 triples games without Peter Gibbons.
SuperWang and Peter Gibbons have won 5 games without Gilligan.
Does this mean that we qualify? The way I see it, part in 2) means we only need 2 wins without the other player apiece.
As i worded it i will explain:
You have 12 wins together so n=12. That means you need only 3 wins (15-n) in combination of eqch of 3 players together, and your numbers are 8/15/5 so you qualify.
You would not qualify if your numbers are for example 8/15/2 because in that case SuperWang and Petter Gibbons are not eligible because they would have 14 triples wins together (12 with Gilligan and 2 with other teammate).
Leehar wrote:In with maasman and lequeen.
I actually think there's not even a need for qualifying requirements. It makes sense when you have too many applicants and you need to pick the best options (eg 1v1 etc), but no sense in limiting the applications entirely.josko.ri wrote:Thanks to Dukasaur or accepting the proposalGilligan wrote:So let me understand that properly -
Gilligan, SuperWang, Peter Gibbons - 12 wins together.
Gilligan and Peter Gibbons have won 8 triples games without SuperWang.
Gilligan and SuperWang have won 15 triples games without Peter Gibbons.
SuperWang and Peter Gibbons have won 5 games without Gilligan.
Does this mean that we qualify? The way I see it, part in 2) means we only need 2 wins without the other player apiece.
As i worded it i will explain:
You have 12 wins together so n=12. That means you need only 3 wins (15-n) in combination of eqch of 3 players together, and your numbers are 8/15/5 so you qualify.
You would not qualify if your numbers are for example 8/15/2 because in that case SuperWang and Petter Gibbons are not eligible because they would have 14 triples wins together (12 with Gilligan and 2 with other teammate).
Wouldn't Superwing & Peter have (12+8/12+15=) 20/27 with gilligan respectively, and 2 with other teammate?
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