Given that we have 49 teams signed up, we will have 15 groups of 3 and 1 group of 4 all chosen randomly.
The groups of 3 will play a modified double-elimination bracket (see spoiler above).
The group of 4 will play a standard double-elimination bracket (see diagram above).
hide: Modified 3-team double-elimination bracket
All teams will play each other once in a match-up. As soon as a team loses 2 match-ups, they are eliminated and the remaining teams will play until one team loses 2 match-ups in the round. In the event that all three teams each have a loss after the round robin play, a special 3-team match-up will be played (1 game on each home map plus 1 random map) with the team winning the most games moving on to the next round. In the event that two teams win two match-ups each, they will play a final match-up (home maps plus 1 random map) to determine a winner.
So for the Group of 3 persons :
As far as I understand. I play against everyone in my group once. ( playing against another team is 3 game 1 home 1 away 1 random round 1 and 5 game, 2 home 2 away 1 random round 2). It is group of 3 teams.
So it is :
Team 1 VS Team 2
Team 1 vs Team3
Team 2 vs team 3
If one one of the 3 team lose twice they are eliminated. This one for Round 1.
Now that we are in round 2 we should be 16 team, splitted into 4 group
16 teams grouped in 4s by ranking (see below).
Double-elimination brackets for each group (see diagram above).
5 games at a time (2 on each home map, 1 on random map).
Match-up winner determined by best of 5.
Winner of the bracket moves on to the next round.
So we should have a standart double elimination brakets since we are 4. for now. And not play again against same team.