Peanut's 3X Double-Elimination - Doubles[TPA3] Completed

by **Donelladan** on Thu Apr 18, 2013 7:58 am

Seems not clear at all. This is what I read

Round 1
Given that we have 49 teams signed up, we will have 15 groups of 3 and 1 group of 4 all chosen randomly.
The groups of 3 will play a modified double-elimination bracket (see spoiler above).
The group of 4 will play a standard double-elimination bracket (see diagram above).

hide: Modified 3-team double-elimination bracket

All teams will play each other once in a match-up. As soon as a team loses 2 match-ups, they are eliminated and the remaining teams will play until one team loses 2 match-ups in the round. In the event that all three teams each have a loss after the round robin play, a special 3-team match-up will be played (1 game on each home map plus 1 random map) with the team winning the most games moving on to the next round. In the event that two teams win two match-ups each, they will play a final match-up (home maps plus 1 random map) to determine a winner.

So for the Group of 3 persons :

As far as I understand. I play against everyone in my group once. ( playing against another team is 3 game 1 home 1 away 1 random round 1 and 5 game, 2 home 2 away 1 random round 2). It is group of 3 teams.
So it is :
Team 1 VS Team 2
Team 1 vs Team3
Team 2 vs team 3

If one one of the 3 team lose twice they are eliminated. This one for Round 1.

Now that we are in round 2 we should be 16 team, splitted into 4 group

Round 2
16 teams grouped in 4s by ranking (see below).
Double-elimination brackets for each group (see diagram above).
5 games at a time (2 on each home map, 1 on random map).
Match-up winner determined by best of 5.
Winner of the bracket moves on to the next round.

So we should have a standart double elimination brakets since we are 4. for now. And not play again against same team.

by **chapcrap** on Thu Apr 18, 2013 10:02 am

donelladan wrote:Seems not clear at all. This is what I read

Round 1
Given that we have 49 teams signed up, we will have 15 groups of 3 and 1 group of 4 all chosen randomly.
The groups of 3 will play a modified double-elimination bracket (see spoiler above).
The group of 4 will play a standard double-elimination bracket (see diagram above).

hide: Modified 3-team double-elimination bracket
All teams will play each other once in a match-up. As soon as a team loses 2 match-ups, they are eliminated and the remaining teams will play until one team loses 2 match-ups in the round. In the event that all three teams each have a loss after the round robin play, a special 3-team match-up will be played (1 game on each home map plus 1 random map) with the team winning the most games moving on to the next round. In the event that two teams win two match-ups each, they will play a final match-up (home maps plus 1 random map) to determine a winner.

So for the Group of 3 persons :

As far as I understand. I play against everyone in my group once. ( playing against another team is 3 game 1 home 1 away 1 random round 1 and 5 game, 2 home 2 away 1 random round 2). It is group of 3 teams.
So it is :
Team 1 VS Team 2
Team 1 vs Team3
Team 2 vs team 3

If one one of the 3 team lose twice they are eliminated. This one for Round 1.

Now that we are in round 2 we should be 16 team, splitted into 4 group

Round 2
16 teams grouped in 4s by ranking (see below).
Double-elimination brackets for each group (see diagram above).
5 games at a time (2 on each home map, 1 on random map).
Match-up winner determined by best of 5.
Winner of the bracket moves on to the next round.

So we should have a standart double elimination brakets since we are 4. for now. And not play again against same team.

I'm not sure what invites were sent or games played, but I believe this interpretation is correct. It is essentially, 3 rounds of small double elimination brackets. There were not enough sign ups to run the tournament as intended and I allowed peanut to modify the play slightly in Round 1. In rounds 2 and 3, the double elimination bracket it what was intended to be used.

peanutman wrote:
show: Diagram of a 4-team double-elimination bracket

by **DaveH** on Thu Apr 18, 2013 2:22 pm

Thanks for the inputs, though I read Peanut's instructions slightly differently.

Firstly, the one team of 4 is playing the correct double elimination format - no problem.

The remainder have played in groups of 3 a matchup (which is a home game, an away game and a random game) against each of the other two teams i.e. 9 games.

This is where I picked the tournament up and there is one group that have won one matchup each, so they ahave played a three- team game as specified. - no problem

The remainder have had one team that lost twice and so are out, leaving the other two teams to play each other until one team wins TWO matchups.

One matchup has been decided and so I have sent out the second set of the same games to determine which team wins the second match in which case there may then be a third set of the same games to determine which team goes through.

Note that we are still in the first round, though I may have confused over the use of "set" as a label.

After the conclusion of this Round 1 there will be 16 teams organised and ranked as 4 groups of 4 teams that can play a standard double elimination tournament. - no problem

Note that I am not trying to be difficult and do not care too much what system we play, but I am just trying to keep to the original rules. Had Peanut written "All teams will play each other once in a match-up. As soon as a team loses 2 match-ups, they are eliminated and the remaining teams will play until one team loses ONE match-up in the round." than I would agree that we are now ready to move on to the 4 x 4 format, but he put "... win TWO matchups in the round"

Perhaps I need to take into account the earlier matchup between the two teams and so avoid a second set of games other than if a decider is required?

by **DaveH** on Thu Apr 18, 2013 2:35 pm

donelladan wrote:Now that we are in round 2 we should be 16 team, splitted into 4 group

For clarification, we are still in Round 1; the games sent out are the second set of games to form matchup 2 as in "..the remaining teams will play until one team loses TWO match-ups in the round"

As it says "Round" though, I perhaps need to take account of the matchup between the two teams in the three team set of games and only if there was 1 win each have the deciding set?

I'm happy to go wiuth whatever Chap think is the original interpretation of course.

by **Donelladan** on Fri Apr 19, 2013 1:47 am

Ok. Understood. You are right then.

by **Robespierre__** on Sat Apr 20, 2013 1:41 pm

Peanut still seems active ... why the heck would he not clarify?? :p

by **DaveH** on Mon Apr 22, 2013 11:50 am

Robespierre__ wrote:Peanut still seems active ... why the heck would he not clarify?? :p

Good point - I have pm'ed and I'll communicate any feedback.

by **UMiami11** on Wed Apr 24, 2013 11:42 am

DaveH, I interpreted the rules the same as you.

by **merch313** on Sun Jun 02, 2013 5:05 pm

Tourney active

by **DaveH** on Thu Jun 06, 2013 5:24 am

We now have 15 of the 16 teams into the final sets of games and awaiting a joiner into the 4-team bracket final. Teams have reached the final stage through 3 different methods due to the different number of entrants than planned, so I can't see a fair way of ranking teams ahead of distributing them according to the Serpentine system (which would form 4 groups viz. 1, 8, 9, 16 & 2, 7, 10, 15 & 3, 6, 11,14 & 4,5,13,12) so I intend to randomise the groups if that is acceptable.

by **jetsetwilly** on Mon Jun 24, 2013 2:34 am

Hi, do we have more games coming up soon ?

by **DaveH** on Mon Jun 24, 2013 11:26 am

jetsetwilly wrote:Hi, do we have more games coming up soon ?

Absolutely! We are just awaiting the conclusion of 1 set of three games to determine the final doubles team to join the 15 other teams. Then we can sort into 4 groups of 4 and get the games out.