y=mx+b [Social][Recruiting]

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Re: y=mx+b *Math Made Easy!* [Social][Forming]

Postby Victor Sullivan on Fri Feb 25, 2011 3:38 pm

You thrifty Swifties can be in if you'd like, though I need a direct yes or no from you, Gold Knight ;)
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Re: y=mx+b *Math Made Easy!* [Social][Forming]

Postby slowreactor on Fri Feb 25, 2011 4:14 pm

It's like God answered my prayers - please count me in :D

P.S. what level of math do you think this will go to?
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Re: y=mx+b *Math Made Easy!* [Social][Forming]

Postby Army of GOD on Fri Feb 25, 2011 4:18 pm

I can help up to my highest level of class which is Calc III currently.
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Re: y=mx+b *Math Made Easy!* [Social][Forming]

Postby Victor Sullivan on Fri Feb 25, 2011 4:26 pm

I know it all, though I'm rusty on the non-high school level stuff :P

I appreciate your seriousness, AoG, so I will grant you the TA position, if you so choose to take it. :)
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Re: y=mx+b *Math Made Easy!* [Social][Forming]

Postby 40kguy on Fri Feb 25, 2011 4:29 pm

sure i need help from time to time
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Re: y=mx+b *Math Made Easy!* [Social][Forming]

Postby Haggis_McMutton on Fri Feb 25, 2011 4:30 pm

Well, i'm in 11 usergroups currently, might as well make it a dozen.
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Re: y=mx+b *Math Made Easy!* [Social][Forming]

Postby Victor Sullivan on Fri Feb 25, 2011 4:31 pm

Lol, okay guys, I'll include y'all.
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Re: y=mx+b *Math Made Easy!* [Social][Forming]

Postby 40kguy on Fri Feb 25, 2011 4:35 pm

Haggis_McMutton wrote:Well, i'm in 11 usergroups currently, might as well make it a dozen.

i will make it two dozen :)
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Re: y=mx+b [Social][Recruiting]

Postby Victor Sullivan on Fri Feb 25, 2011 4:35 pm

Alright, gents, I just sent the e-ticket :)
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Re: y=mx+b [Social][Recruiting]

Postby slowreactor on Fri Feb 25, 2011 4:42 pm

Well - I'm past multivar calc right now, struggling a little bit on linear algebra. I can help up to there, but any further I'm done for xD
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Re: y=mx+b [Social][Recruiting]

Postby mviola on Fri Feb 25, 2011 4:44 pm

I'll join, I'm in Calc 3 right now. I'll take whatever help I can get. :)
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Re: y=mx+b [Social][Recruiting]

Postby jfugere on Fri Feb 25, 2011 5:19 pm

I'm a math lover, and I was a math teacher until teaching for pay became a crime in my state. I'll join either side.
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Re: y=mx+b [Social][Recruiting]

Postby tkr4lf on Fri Feb 25, 2011 5:36 pm

I'm actually having to take a developmental algebra class right now, it's been so long since high school and I simply forgot all that crap. I could use help from time to time, more so when I get into actual College Algebra. I'll join up.
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Re: y=mx+b [Social][Recruiting]

Postby Victor Sullivan on Fri Feb 25, 2011 5:39 pm

Cool, thanks for joining, guys. I've already sent the e-ticket, so I'll just add you three when the forum's up. Feel free to remind me to add you, I might forget :|
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Re: y=mx+b [Social][Recruiting]

Postby iamkoolerthanu on Fri Feb 25, 2011 5:47 pm

I will join.. IDK how often I will ask questions here, but if I ever need to ask I definitely will :)
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