Conquer Club

I have finally come up with an equation that can predict how much a player will complain about the dice. Here it is, please see the explanation

C = (M*S^2)/(F*SK)

C is the number of complaints a player will make per year.

M is the number of medals a player has. Notice that C is proportional to the number of medals, so a player doubles how many medals he has, he will complain twice as much.

S is score. Notice that C is proportional to S squared. This means that if a players score doubles, he will then whine about the dice 4 times as much.

F is the number of friends a player has. C is inversely proportional to number of friends. So if a player doubles the number of friends he has, then his dice complaints will be cut in half.

Sk is how skilled a person is in the game. The more skilled they are the less whining.




P.S. Ok, for all you math geeks and people who like to over analyze, I know there should be a constant in there, just leave it alone.

lol

how exactly is medal count proportional to complaints? shouldn't it be inversely proportional?

slowreactor wrote:how exactly does medals proportional to complaints? shouldn't it be inversely proportional?

i agree, score and medals should both be inversely related rather than directly related...

hwhrhett wrote:

slowreactor wrote:how exactly does medals proportional to complaints? shouldn't it be inversely proportional?

i agree, score and medals should both be inversely related rather than directly related...

Send it in to Mythbusters

e_i_pi wrote:

hwhrhett wrote:

slowreactor wrote:how exactly does medals proportional to complaints? shouldn't it be inversely proportional?

i agree, score and medals should both be inversely related rather than directly related...

Send it in to Mythbusters

Georgerx7di wrote:I have finally come up with an equation that can predict how much a player will complain about the dice. Here it is, please see the explanation

C = (M*S^2)/(F*SK)

C is the number of complaints a player will make per year.

M is the number of medals a player has. Notice that C is proportional to the number of medals, so a player doubles how many medals he has, he will complain twice as much.

S is score. Notice that C is proportional to S squared. This means that if a players score doubles, he will then whine about the dice 4 times as much.

F is the number of friends a player has. C is inversely proportional to number of friends. So if a player doubles the number of friends he has, then his dice complaints will be cut in half.

Sk is how skilled a person is in the game. The more skilled they are the less whining.




P.S. Ok, for all you math geeks and people who like to over analyze, I know there should be a constant in there, just leave it alone.

So, for me: M=1 medal (I'm freaking amazing), S=1188 points, F=0 friends (again, I'm freaking amazing) and Sk=2.5 (what are the units for skill anyhowz?).

Apparently, I'll complain about the dice an undefined amount of times. Is that good?!

Army of GOD wrote:

Georgerx7di wrote:I have finally come up with an equation that can predict how much a player will complain about the dice. Here it is, please see the explanation

C = (M*S^2)/(F*SK)

C is the number of complaints a player will make per year.

M is the number of medals a player has. Notice that C is proportional to the number of medals, so a player doubles how many medals he has, he will complain twice as much.

S is score. Notice that C is proportional to S squared. This means that if a players score doubles, he will then whine about the dice 4 times as much.

F is the number of friends a player has. C is inversely proportional to number of friends. So if a player doubles the number of friends he has, then his dice complaints will be cut in half.

Sk is how skilled a person is in the game. The more skilled they are the less whining.




P.S. Ok, for all you math geeks and people who like to over analyze, I know there should be a constant in there, just leave it alone.

So, for me: M=1 medal (I'm freaking amazing), S=1188 points, F=0 friends (again, I'm freaking amazing) and Sk=2.5 (what are the units for skill anyhowz?).

Apparently, I'll complain about the dice an undefined amount of times. Is that good?!

Sorry cannot define whether that is good or not. Please try again when you have found a friend

Army of GOD wrote:

Georgerx7di wrote:I have finally come up with an equation that can predict how much a player will complain about the dice. Here it is, please see the explanation

C = (M*S^2)/(F*SK)

C is the number of complaints a player will make per year.

M is the number of medals a player has. Notice that C is proportional to the number of medals, so a player doubles how many medals he has, he will complain twice as much.

S is score. Notice that C is proportional to S squared. This means that if a players score doubles, he will then whine about the dice 4 times as much.

F is the number of friends a player has. C is inversely proportional to number of friends. So if a player doubles the number of friends he has, then his dice complaints will be cut in half.

Sk is how skilled a person is in the game. The more skilled they are the less whining.




P.S. Ok, for all you math geeks and people who like to over analyze, I know there should be a constant in there, just leave it alone.

So, for me: M=1 medal (I'm freaking amazing), S=1188 points, F=0 friends (again, I'm freaking amazing) and Sk=2.5 (what are the units for skill anyhowz?).

Apparently, I'll complain about the dice an undefined amount of times. Is that good?!

Just for you : ) Skill will be measured in kilothoughts/seconds^2

I'm not very well adept at mathematics---however, I feel there is a strong correlation between favorable intensity cubes and increased happiness.


--Andy

AndyDufresne wrote:I'm not very well adept at mathematics---however, I feel there is a strong correlation between favorable intensity cubes and increased happiness.


--Andy

Miserably Fooked off from London confirms what Andy wrote