Conquer Club

This is kinda newbie maths, but I need help.

Question:

Adams probability to catch the train is 0.7
Simons probability to catch the train is 0.8

What is the probability that at east ONE of them catches the train?

Anyone? :/

0.75

C.

yeti_c wrote:0.75

C.

I have 5 alternatives, and not one of them is 0.75 :/

PSH!

Give us the alternatives and I may be able to think it out for you.

Skittles! wrote:PSH!

Give us the alternatives and I may be able to think it out for you.

0.56 <--- Not possible.

0.92

0.94

0.96

0.98

P(A or B) = P(A) + P(B) - P(A and B)

when we say P(A or B) here we mean A can occur, B can occur, or both.

P(A and B) here means P(A)*P(B). Since (I assume) we are assuming whether Adam and Simon catch the train are independent of each other (Adam catching the train doesn't affect whether Simon catches the train)

Yeah, I have no idea because I forget all of my probability. Ha. I forget the formula to do it <<

How is it not possible though?

Question:

Adams probability to catch the train is 0.7
Simons probability to catch the train is 0.8

What is the probability that at east ONE of them catches the train?

noteto me:first read then think, so if one has 80% of making it, and the other 70%, it does not matter if both have to take it, just that one does.
so we start with 80%, that being the highest. then in the remaining 20% there is still a 70% chance for adam to catch the train.
(pray he gets it rigth)

That’s 80% PLUS 70% of the remaining 20% for a total of:
80+ (70%x20)= 94%

edbeard wrote:P(A or B) = P(A) + P(B) - P(A and B)

when we say P(A or B) here we mean A can occur, B can occur, or both.

P(A and B) here means P(A)*P(B). Since (I assume) we are assuming whether Adam and Simon catch the train are independent of each other (Adam catching the train doesn't affect whether Simon catches the train)

Dude, you can't use that formula can you, since they aren't depending on each other.


IRT #Skittles

Because the lowest probability is 0.7, which there total must be over.

Someone get sully800 here :/


IRT SirSebster


I don't really know how you solve that equation? :/

oggiss wrote:Dude, you can't use that formula can you, since they aren't depending on each other

that's exactly why you CAN use it.


.8 + .7 - (.8*.7) = 1.5 - .56 = .94

i edited it to make it more comprehensible
i hope its understandable now

edbeard wrote:

oggiss wrote:Dude, you can't use that formula can you, since they aren't depending on each other

that's exactly why you CAN use it.


.8 + .7 - (.8*.7) = 1.5 - .56 = .94

Seems to be the right equation

Thanks both sebster and edbeard

http://www.glamdring.se/files/oggiss.20 ... .33.14.gif


Can anyone solve that one?

The figure shows a white area, I wanna know what the sign is of it in mathematic language. Like those A and B's there.

Thank you

It's just A...

(i.e. Option C)

C.

yeti_c wrote:It's just A...

(i.e. Option C)

C.

k thanks

yeti_c wrote:It's just A...

(i.e. Option C)

C.

i agree

alex_white101 wrote:

yeti_c wrote:It's just A...

(i.e. Option C)

C.

i disagree, i think its either A or B, as it is A including B but i cant remember which one it is.

a) is the Intersection of A & B - i.e. the bit in the middle...
b) is the Union of A & B - i.e. All of the area not including the bit in the middle
c) is just A (Which is the white area)
d) is just B which would be the contents of the circle named B

http://en.wikipedia.org/wiki/Table_of_m ... al_symbols

C.

yeti_c wrote:

alex_white101 wrote:

yeti_c wrote:It's just A...

(i.e. Option C)

C.

i disagree, i think its either A or B, as it is A including B but i cant remember which one it is.

a) is the Intersection of A & B - i.e. the bit in the middle...
b) is the Union of A & B - i.e. All of the area not including the bit in the middle
c) is just A (Which is the white area)
d) is just B which would be the contents of the circle named B

http://en.wikipedia.org/wiki/Table_of_m ... al_symbols

C.

Yeti please dont edit to try and make me look silly........

He didn't edit? :O


Oh, you edited

Moved. Please watch where you're posting from now on ooggss.

wicked wrote:Moved. Please watch where you're posting from now on ooggss.

Forum Nazi... *crack of the whip*

Would you have her any other way?

She could move that left foot away from the body a bit.

I can see it flying into your general direction