Ok. 5 eliminations so far, 1 more guaranteed. We can have between 6 and 9 players eliminated this round. A lot, considering I was expecting no eliminations in round 1.
So if:
6 players are eliminated and 18 remain = 5 3-player games in 6 different groups
7 players are eliminated and 17 remain = 1 random rescue + 5 3-player games in 6 different groups
8 players are eliminated and 16 remain = 6 4-player games in 4 different groups
9 players are eliminated and 15 remain = 7 5-player games in 3 different groups
No matter what: Round 3 will be 2-player games so a maximum of 1 player will be saved.
If Round 2 was 3-player games, then rounds 4 and 5 will be 4 or 5 player games.
If Round 2 is anything else, then round 4 will be 3-players and then round 5 will fill the last slot.
Round 6 and 7 will be 7 and 8 player games (in whatever order necessary). (If we even get that far)
Any rounds left over will be 6-player games or smaller. If needed, we will do a poll to see the best way to find a winner. (This tournament isn't very good at picking a winner).
The way random recoveries will work is that players who made it farther get more chances.
So, players eliminated in round 1 get their name added to the random.org list ONE TIME. In round 2, they all have an equal chance. Players eliminated in round 2 get their name added to the list TWICE. So in round 3, each the round 2 players has twice the chance of a round 1 player. Likewise for round 3 etc.
